What is the true solution to in 20+ in 5= 2 in x?
х= 5
x= 10
х= 50
x= 100

answer:

your answer is: c. 196 7/8 in^3.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation:

the answer is 5/14.

hope this .