How many permutations are there of the letters in the words (a) triskaidekaphobia (fear of the number 13)? (b) (estimating something as worthless)? (c) (a lung disease caused by inhaling fine particles of silica)? (this word is, by some accounts, the longest word in the english language.) (d) dermatoglyphics (skin patterns or the study of them)? (this word is the (current) longest word in the english language that doesn't repeat a letter; another word of the same length is uncopyrightable.13)

Hello!

Let's start with the word TRISKAIDEKAPHOBIA wich has 17 letters (some of them repeat, but it does not matter in this problem)

We want to know how many permutations we can do with 17 letters: then think this way, Lets compose a word. The first letter of this word has 17 options, the second letter of the word has 16 options (you already took one of the set) the third letter of the word has 15 options, and so on.

The total number of permutations is the product of the number of options that you have for each letter, this is:

17*16*15*14**3*2*1 = 17! = 3.6e+14

(b) now we have 30 letters in total, using the same reasoning as before, here we have 30! permutations; this is

30! = 2.65e+32

(c) : now there are 47 letters.

then P = 47! = 2.59e+59

(d) DERMATOGLYPHICS: here are 18 letters, then:

p = 18! = 6.4e+15

answer: the answer to your question is parallel

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10