Abasketball player has a free throw percentage of 92% . what is the probability she misses at least one of his next 27 free throws?

89.5%

Step-by-step explanation:

The probability of missing at least one of 27 throws is 1 minus the probability of not missing any throws.

P = 1 − (0.92)^27

P ≈ 0.895

There's about a 89.5% probability that the player misses at least one throw out of 27.

ou would have 12 of each

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a