In a lottery, 6 numbers are randomly sampled without replacement from the integers 1 to 38. their order of selection is not important. find the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket out of the 38 possible numbers.

Our required probability is 0.328.

Step-by-step explanation:

Since we have given that

there is number on the lottery is from 1 to 38.

6 numbers are selected.

We need to find the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket.

So, it should be other than 6 numbers.

Remaining numbers = 38-6 = 32

So, our probability becomes

Hence, our required probability is 0.328.

the answer is vanilla

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.