Aprojectile is fired upward from the ground with an initial velocity of 300 feet persecond. neglecting air resistance, the height of the projectile at any time t can bedescribed by the polynomial function p(t) = ­16t2 + 300

a. find the height of the projectile when t = 1 second.
b. find the height of the projectile when t = 5 seconds.
c. how long will it be until the object hits the ground?

P(t) = - ­16t*2 + 300t

For t = 1 second we have:

P(1) = - 16*1^2 + 300*1

P(1) = 284 ft

The height of the projectile after 1 second is 284 feet.

Step-by-step explanation:

Hope this helps :))

i do not know the answer i am sorry

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form