When converted to an iterated integral, the following double integral is easier to evaluate in one order than the other. find the best order and evaluate the integral. modifyingbelow integral from nothing to nothing integral from nothing to nothing with upper r2 x secant squared (xy )da; requals{(x comma y ): 0 less than or equals x less than or equals startfraction pi over 3 endfraction comma 0 less than or equals y less than or equals 1 }