The durations in seconds of their first three flights can be represented by consecutive odd integers, such that the product of the first and third was equal to 4 led than five times the second. find the durations of their first three flights.

Step-by-step explanation:

The first important detail is ''consecutive odd integers'', which can be express as:

Then, we apply this definitions to the conventional language to convert it to math language:

The product of the first and third:

4 less than five times the second:

So, the expression would be

If we solve this equation, will result: ; which is an second grade equation.

To solve it, we need to find two number that their multiplication results in 6, but their subtract results in 1. Being those numbers, 3 and 2.

So, results are

But, time cannot be negative, so, we only take the first value.

If we substituted in the initial expression of the odd integers, we will have:

Hence, the numbers are 3, 5 and 7.

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316