9. a rectangle has a width that is 2 feet longer than four times the length. what is the length of the rectangle
if the perimeter is 64 feet? (hint: draw a picture and use algebra to solve)

6 feet

Step-by-step explanation:

Perimeter = 2L + 2W

Since you know the perimeter is 64 feet, you would plug that into the perimeter side.

64 = 2L + 2W

You also know the width is 2 feet longer than 4 times the length.

64 = 2L + 2(2 + 4L)  > Multiply 2 * 2 and 2 * 4l

64 = 2L + 4 + 8L  > Subtract 4 from each side

-4           -4

60 = 2L + 8l > add these two

60 = 10L

/10   /10 > divide by 10 on each side

6 = L

Now that we know the length, find the width.

64 = 2(6) + 2(2 + 4(6)) > multiply 2 * 6 and 4 * 6

64 = 12 + 2(2 + 24) > add 24 and 2

64 = 12 + 2(26) > multiply 2 and 26

Before you go any further, you now know that the width is 26 feet. Continue solving.

64 = 12 + 52

64 = 64

Everything checks out.

The length is 6 feet and the width is 26 feet.

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol

168

step-by-step explanation:

first off, we know that he drove 3.5 hours at a rate of 48 mph.

knowing that, we want to see how many miles he drove all-together.

in this case, we can just multiply 48 by 3.5.

48 * 3.5 = 168