What is the solution of the system? use substitution.
4x – y = 5
3x – 7 = 2
a) (3, 7)
b) (7, -7)
c) (-3, 7)
d) (3/4, 2/5

Hi

4x-y=5

3x-7=2

We need to solve 3x-7=2 for x

Let's start by adding 7 to both sides

3x-7+7=2+7

3x=9

Now just divide both sides by 3 so we can find the value for x

3x/3=9/3

x=3

Now substitute 3 for x in 4x-y=5

4x-y=5

(4)(3)-y=5

-y+12=5

Now add -12

-y=12-12=5-12

-y=-7

Divide both sides by -1 so we can eliminate the negative sign

-y/-1=-7/-1

y=3

The answer is A

(3,7)

I hope that's help:0

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier