Mathematics, 19.10.2019 02:30 wickedskatboarder

Based on a poll, among adults who regret getting tattoos, 23% say that they were too young when they got their tattoos. assume that nine adults who regret getting tattoos are randomly selected, and find the indicated probability. complete parts (a) through (d) below.(a) find the probability that none of the selected adults say that they were too young to get tattoos.(b) find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.(c) find the probability that the number of selected adults saying they were too young is 0 or 1.(d) it we randomly select 9 adults. is 1 a significantly low number who day that they were too young to get tattoos?

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Answer from: garacey241

a) There is a 9.52% probability that none of the selected adults say that they were too young to get tattoos.

b) There is a 25.28% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c) There is a 35.1% probability that the number of selected adults saying they were too young is 0 or 1.

d) 1 is not a significantly low number who say that they were too young to get tattoos.

Step-by-step explanation:

For each adult questioned, there are only two answers possible, two outcomes. Either they were too young when they got their tattoos, or they were not. So this means that we can solve this problem as binomial distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

Nine adults are sampled, so n = 9 .

23% say that they were too young when they got their tattoos, so p = 0.23 .

(a) Find the probability that none of the selected adults say that they were too young to get tattoos.

This is P(X = 0)

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{9,0}.(0.23)^{0}.(0.77)^{9} = 0.0952$

There is a 9.52% probability that none of the selected adults say that they were too young to get tattoos.

(b) Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.

This is P(X = 1)

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{9,1}.(0.23)^{1}.(0.77)^{8} = 0.2558$

There is a 25.28% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

P = P(X = 0) + P(X = 1) = 0.0952 + 0.2558 = 0.351

There is a 35.1% probability that the number of selected adults saying they were too young is 0 or 1.

(d) It we randomly select 9 adults. Is 1 a significantly low number who say that they were too young to set tattoos?

We say that a value x is significantly low if:

$P(X \leq x) \leq 0.05$

For 1, we have

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0952 + 0.2558 = 0.351$ .

A 35.1% probability is greater than a 5% probability, so 1 is not a significantly low number who say that they were too young to get tattoos.

Answer from: aleiahmartin

Step-by-step explanation:

a) There is a 9.52% probability that none of the selected adults say that they were too young to get tattoos.

b) There is a 25.28% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

c) There is a 35.1% probability that the number of selected adults saying they were too young is 0 or 1.

d) 1 is not a significantly low number who say that they were too young to get tattoos.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And is the probability of X happening.

In this problem, we have that:

Nine adults are sampled, so .

23% say that they were too young when they got their tattoos, so .

(a) Find the probability that none of the selected adults say that they were too young to get tattoos.

This is P(X = 0)

There is a 9.52% probability that none of the selected adults say that they were too young to get tattoos.

(b) Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos.

This is P(X = 1)

There is a 25.28% probability that exactly one of the selected adults says that he or she was too young to get tattoos.

There is a 35.1% probability that the number of selected adults saying they were too young is 0 or 1.

(d) It we randomly select 9 adults. Is 1 a significantly low number who say that they were too young to set tattoos?

We say that a value x is significantly low if:

For 1, we have

A 35.1% probability is greater than a 5% probability, so 1 is not a significantly low number who say that they were too young to get tattoos.

Answer from: Quest

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.

Answer from: Quest

constants mean the stopped points or the points on a graph that nothing is changing, hope this

step-by-step explanation:

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