Consider the polynomial functionp(x)=x³-8x²-29x+180.state the zeros of p.

x = 4 , x = 9 , x = -5

Step-by-step explanation:

Given: P(x)=x³-8x²-29x+180

Find the zeros of the polynomial.

First we factor the polynomial and then set each factor to 0.

P(x)=0

Put x=4 into P(x)

P(4)=0

Divide the polynomial by x-4

Set each factor to 0

x - 4 = 0   |    x - 9 = 0      |       x + 5 = 0

x = 4 , x = 9 , x = -5

Zeros of the polynomial, P(x), are -5,4 and 9

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