Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. assume that the cost of materials for the base is$$12 dollars per square meter, and the cost of materials for the sides is $$8 dollars per square meter. the height of the box is three times the width of the base. what’s the least amount of money we can spend to build such a container?

265.25

Step-by-step explanation:

Given

Volume of box

height is 3 times the width

let height, length and breadth be H, L & B

4=B^2\times L[/tex]

Cost of side walls $

Cost of base $

Cost of side walls

Cost of base

Total cost

differentiate C w.r.t B to get minimum cost

L=2.19 m

C=$ 265.25

b is the final answer! : )

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.