Astraight line passed through p(-4,8) and q(0-2). find the equation of the perpendicular
bisector of the line pq

y = 2/5x + 11/5

Step-by-step explanation:

midpoint:

P(-4 , 8)

Q(0 , -2)

[(-4+0)/2 , (8-2)/2]

=(-4/2 , 6/2)

=(-2 , 3)

gradient:

m = (8+2)/(-4-0)

= 10/(-4)

= -5/2

= 2/5 (opp. of reciprocal)

equation:

y = mx + c

y = 2/5x + c

3 = 2/5(-2) + c (using coordinate of midpoint)

c = 3 + (-4/5)

= 11/5

y = 2/5x + 11/5

(Correct me if i am wrong)

x^5/3y^1/3 the correct answer

hope it

the system of inequalities is

step-by-step explanation:

step 1

find the equation of the dashed line

we have the points

(0,0) and (3,1)

the line passes through the origin, so, is a direct variation

find the slope

the equation of the dashed line is

the solution of the inequality a s the shaded area above the dashed line

therefore

the equation of the inequality a is

step 2

find the equation of the solid line

we have the points

(4,0) and (0,4)

find the slope

the equation of the solid line is

the solution of the inequality b s the shaded area below the solid line

therefore

the equation of the inequality b is

step 3

the system of inequalities is