Iam a 2 digit number the sum of my digits is 8 my tens digit is 2 more than my ones digit what number am i

53

5 + 3 = 8

5 - 2 = 3

53

Step-by-step explanation:

let's call it xy :

x + y =8

x = y + 2

replace x in the first equation with y + 2

x + y = 8➡ y + 2 + y = 8 ➡ 2y = 6 ➡ y = 3

since x was 2 more than y then ➡ 3 + 2 = 5

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step-by-step explanation:

just for that im not answering

where is the diagram? shown below where? ?

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