The point slope form of the equation of the line that passes through (-5,-1) and (10,-7) is y+7=-2/5(x-10). what is the standard form of the equation for this line?

a. 2x-5y=-15
b. 2x-5y=-17
c. 2x+5y=-15
d. 2x+5y=-17

Option C

The standard form of the equation for y + 7 = -2/5(x - 10) is 2x + 5y = -15.

Solution:

Need to determine standard form of equation of line passing through points (-5, -1) and (10, -7) and having slope form as  

Standard form of equation of line is such that terms having variables are on left hand side and constant terms on right hand side.

So let’s simplify given slope form.

On opening the brackets we get

=> 5(y + 7) = -2x +20

=> 5y + 2x = 20 – 35

=> 2x +5y = -15

Hence the standard form is 2x + 5y = -15.

597

step-by-step explanation:

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.