What is the solution for the system of linear equations y=4x + 1 and 2x + y = 13 ?

The solution for the system of linear equations y = 4x + 1 and 2x + y = 13 is (x, y) = (2, 9)

Solution:

Given, two equations are y = 4x + 1 ⇒ (1) and 2x + y = 13 ⇒ (2)

We have to find the solution of the above system of equations.

Now, substitute the y value of equation (1) in place of y of the equation (2)

Then, eqn (2) becomes ⇒ 2x + (4x + 1) = 13

⇒ 2x + 4x + 1 = 13  

⇒ 6x = 13 – 1  

⇒ 6x = 12  

⇒ x = 2

Substitute x value in (1)

Eqn (1) becomes ⇒  y = 4(2) + 1

⇒ y = 8 + 1 ⇒ y = 9

Hence, the solution for the given system of equations is (x, y) = (2, 9)

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk