Aline has a slope of m=12 and the point (-2,8) lies on the line. which of the following represent the line? select two answers.
a. y=12x-16
b. y=12x+32
c. y-8=12(x+2)
d. y+8=12(x-2)

b. y=12x+32, c. y-8=12(x+2)

Step-by-step explanation:

point -slope form equation

(y-y1) = m(x-x1)

(y - 8) = 12(x + 2) point slope form

y - 8 = 12x +24

y = 12x + 32 slope intercept form

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.