Aman throws a ball into the air with a velocity of 96 ft/s. use the formula h=−16 t 2 + v 0 t to determine when the height of the ball will be 48 feet. round to the nearest tenth.

Assuming that v0 represents the initial velocity, then v0 = 96 ft/s. Substitute this value into h(t) and set the equation equal to 48. Then, write this quadratic equation in standard form, which is ax² + bx+ c = 0, where a, b, and c are constants. Either use factoring or the Quadratic Function to solve the equation for t. Remember that t must be positive, because it represents a unit of time.

t=5.4 and t=0.6.

Step-by-step explanation:

The height of the ball (in feet) after time t is defined by the function

where, is initial velocity.

It is given that a man throws a ball into the air with a velocity of 96 ft/s.

Substitute v=96 in the above function.

We need to find the time at which the height of ball is 48 feet.

     .... (1)

Quadratic formula for is

In equation a=16, b=-96 and c=48. Using quadratic formula we get

and

and

Round the answer to the nearest tenth.

and

Therefore, the height of ball will be 48 feet at t=5.4 and t=0.6.

60: 45 =12: 9 =4: 3 so the answer is 4: 3