In a rock-paper-scissors game, a winner gets 5 points and a loser gets 2 points. after a man played this game 20 times, his total score was 67 points. how many times did he win, and how many times did he lose

The man wins 9 times and looses 11 times in the rock - paper-scissor game.

Step-by-step explanation:

Let us assume that in the game:

Number of times  man wins the games = x times

Number of times  man loses the games = y times

Total number of attempts = 20

Points after winning = 5

Points after loosing = 2

Now, according to the question:

       x  + y =20

and 5 x + 2 y = 67

Now, from (1) y = 20-x,     put in (2)

5x + 2y = 67       ⇒           5x + 2(20 -x)  = 67

or, 5x -2x = 67 - 40

or, 3x = 27

⇒ x = 27/3 = 9

then y = 20 - x = 20 - 9 = 11

⇒ x = 9 and y = 11 is the solution of the given system.

Hence, the man wins 9 times and looses 11 times in the rock - paper-scissor game.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: