Joe wants to enlarge the rectangular pumpkin patch located on his farm. the pumpkin patch is currently 40 meters wide and 60 meters long. the new pumpkin patch will be 3x meters wider and 5x meters longer than that of the original pumpkin patch. which of the following functions will give the area of the new pumpkin patch in square meters?

The area of new pumpkin patch is    =  15 x² + 380 x + 2400

Step-by-step explanation:

Given as :

The length of rectangular patch = L = 40 meters

The width of rectangular patch = W = 60 meters

So, The area of rectangular patch = Length × Width

Or, =  L × W

So ,    =  40 meters × 60 meters

Or,   =  2400 meters²

Again The Width of new Patch = ( 40 + 3 x ) meter

And     The Length of new Patch = ( 60 + 5 x )  meter

Or,  =  L × W

So ,  =  ( 40 + 3 x ) meters × ( 60 + 5 x ) meters

Or,    = 2400 + 200 x + 180 x + 15 x²

Or,    =  15 x² + 380 x + 2400

Hence The area of new pumpkin patch is    =  15 x² + 380 x + 2400  Answer

answer: about 22.67

step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1