For each of the following claims, fill in the blanks in the provided hypotheses with inequalities.

if your answer is "less than," type: <

if your answer is "greater than," type: >

if your answer is "less than or equal to," type: < =

if your answer is "greater than or equal to," type: > =

if your answer is "equal to," type: =

if your answer is "not equal to," type: /=

(a) theory to be tested: the average number of children per household in the united states is less than 3.

h0: ? 3 and ha: ? 3

(b) theory to be tested: the average weight of tamu students is greater than 110 pounds.

h0: ? and ha: ?

(c) theory to be tested: the average diameter of saguaro cacti is not 2.1 feet.

h0: ? 2.1 and ha: ? 2.1

(d) theory to be tested: in belarus (former member of the soviet union, located near chernobyl), the average life span is under 70 years.

h0: ? 70 and ha: ? 70

“a term can be a signed number, a variable, or a constant multiplied by a + sign or j sign. in , the terms are 5x , 3y and 8. when a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.” i hope this you.

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.