Use △bcd in the figure shown.

the graph with x-coordinate marks -3, 0, 3 and y-coordinate mark -3, 0, 3. the triangle bcd with coordinates b at (-3, 3), c at (4, 1), d at (0, -2).

choose the correct drop-down menu item in each.

the image of (rx-axis ∘ ry-axis)(△bcd) the image r(180°, o) (△bcd).
is equivalent
is not equivalent
the image of (ry-axis ∘ rx-axis)(△bcd) the image r(180°, o) (△bcd).
is equivalent
is not equivalent

true

step-by-step explanation:

nope.   happens to me as well.

-aparri

25.3

step-by-step explanation:

1st step

add 3+6

=9

multipy 9*3

=37

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.