Solve the system of equations by substitution and show work.
y=−6x+13
y=3x+4

x= 1 , y = 7

Step-by-step explanation:

y = -6x + 13 equation 1

y = 3x + 4 equation 2

substitute y = 3x + 4 into equation 1 , then we have

3x + 4 = - 6x + 13

collect the like terms , we have

3x + 6x = 13 - 4

9x = 9

x = 1

substitute x = 1 into equation 2 , we have

y = 3(1) + 4

y = 3 + 4

y = 7

Therefore : x = 1 and y = 7

(1, 7 )

Step-by-step explanation:

Given the 2 equations

y = - 6x + 13 → (1)

y = 3x + 4 → (2)

Substitute y = 3x + 4 into (1)

3x + 4 = - 6x + 13 ( add 6x to both sides )

9x + 4 = 13 ( subtract 4 from both sides )

9x = 9 ( divide both sides by 9)

x = 1

Substitute x = 1 into (2) for corresponding value of y

y = 3(1) + 4 = 3 + 4 = 7

Solution is (1, 7 )

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²