On a particular production line, the likelihood that a light bulb is defective is 5%. ten light bulbs are randomly selected. what are the mean and variance of the number of defective bulbs?

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

Step-by-step explanation:

Consider the provided information,

Let X is the number of defective bulbs.

Ten light bulbs are randomly selected.

The likelihood that a light bulb is defective is 5%.

Therefore sample size is = n = 10

Probability of a defective bulb = p = 0.05.

Therefore, q = 1 - p = 1 - 0.05 = 0.95

Mean of binomial random variable:

Therefore,

Variance of binomial random variable:

Therefore,

Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.

only 10/60 isn't equivalent

hope this : )

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: