Birth weights of full-term babies in a certain area are normally distributed with mean 7.13 pounds and standard deviation 1.29 pounds. a newborn weighing 5.5 pounds or less is a low-weight baby. what is the probability that a randomly selected newborn is low-weight? do not round, and do not convert the probability as a percentage.

Step-by-step explanation:

Birth weights of full term babies are normally distributed with mean 7.13 pounds and standard deviation 1.29 pounds. Using normal distribution,

z = (x - μ) /σ

Where μ = mean

σ = standard deviation.

x = Birth weights of full term babies

From the information given,

μ = 7.13

σ = 1.29

x = 5.5

the probability that a randomly selected newborn is low-weight means that the newborn is weighing 5.5 pounds or less.

For P(x lesser than or equal to 55) ,

Z= (5.5-7.13)/1.29 = -1.63 /1.29 = -1.263

From the normal distribution table, the value of z = -1.263 = 0.1038

P(x lesser than or equal to 55) = 0.104

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

42

step-by-step explanation: