For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. what is the number of variations in sign for the sequence 1, –3, 2, 5, –4, –6 ?
a. 1
b. 2
c. 3
d. 4
e. 5

Option C.

Step-by-step explanation:

The given given sequence is

1, –3, 2, 5, –4, –6

We need to find the pairs of consecutive terms of the sequence and their product.

Pairs of consecutive terms | Product

     1, -3                                  -3

     -3, 2                                  -6

      2, 5                                  10

      5, -4                                -20

     -4, -6                                 24

Here the product of three pairs of consecutive terms is negative.

The number of variations in sign for the sequence is 3. Therefore, the correct option is C.

it should be a and d. lmk if i'm wrong xd

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people