Which two points are on the graph of y=-x+ 3?
o (1, 2), (0, -3)
o (0,3), (4, -1)
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o (-1, -2), (1, 4)
o (4, -1), (1,3)

(0,3), (4, -1)

Step-by-step explanation:

we have

This is a linear equation (The graph is a line)

we know that

If a ordered pair is on the graph of the line, then the ordered pair must satisfy the equation of the line

Verify each case

case 1) (1, 2), (0, -3)

First point

x=1,y=2

substitute in the equation and then compare the result

---> is true

so

The first point is on the graph

Second point

x=0,y=-3

substitute in the equation and then compare the result

---> is not true

so

The second point is not on the graph

therefore

The two points are not on the graph

case 2) (0,3), (4, -1)

First point

x=0,y=3

substitute in the equation and then compare the result

---> is true

so

The first point is on the graph

Second point

x=4,y=-1

substitute in the equation and then compare the result

---> is true

so

The second point is on the graph

therefore

The two points are on the graph

case 3) (-1, -2), (1,4)

First point

x=-1,y=-2

substitute in the equation and then compare the result

---> is not true

so

The first point is not on the graph

therefore

The two points are not on the graph

case 4) (4, -1), (1,3)

First point

x=4,y=-1

substitute in the equation and then compare the result

---> is true

so

The first point is on the graph

Second point

x=1,y=3

substitute in the equation and then compare the result

---> is not true

so

The second point is not on the graph

therefore

The two points are not on the graph

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you