How do i find out what sets of points are on the line y=6x-4?
a.(0,-4) (26,5)
b.(0,-4) (5,26)
,0) (26,5)
,0) (5,26)

For each point, put the first number into the equation in place of 'x',
and put the second number into the equation in place of 'y', and then
see whether the equation makes sense.  If it does, then that point is
on the line.  If it doesn't, then it's not.

Example:

The equation is     y = 6x - 4

Choice 'C', point    (-4, 0)

Put the ' -4 ' in place of 'x', and put the ' 0 ' in place of 'y'.
Then the equation says
                                             0 = 6(-4) - 4

                                             0 = -24 - 4

                                             0 = -28

Does that make sense to you ?    If it does, then math is not your game.

The equation is not a true statement.
So the point  (-4, 0) in not on the line.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.