Which of the two functions below has the smallest minimum y-value?

f(x)=x^5-2
g(x)=3x^2+1

The correct option is B). f(x)

The minimum value for y belongs to f(x) at x=0 and f(0)=(-2)

Step-by-step explanation:

The given two functions are f(x)= and g(x)=

To find which function got minimum value for y :

For function f(x)=  

Using concept of Maxima and Minima,

Function : f(x)=

Differentiating the function we get,

f(x)=

Take f(x)=0

x=0

Therefore, f(x)=f(0)=0-2=(-2)

For function g(x)=

Using concept of Maxima and Minima,

Function : g(x)=

Differentiating the function we get,

g(x)=

Take g(x)=0

=0

x=0

Therefore, g(x)=g(0)=0+1=1

Thus, The minimum value for y belongs to f(x) at x=0 and f(0)=(-2)

The correct option is B). f(x)

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

b) well because you get well