On a coordinate plane, a piecewise function has 2 lines. the first line has a closed circle at (0, 3) and then goes down through (negative 4, 1) with an arrow instead of an endpoint. the second line has an open circle at (0, 1) and then goes down through (4, negative 1) with an arrow instead of an endpoint.
consider the function given by the graph. what are these values?

f(–2 ) =

f(0) =

f(4) =

f(-2) = 2

f(0) = 3

f (4) = -1

Step-by-step explanation:

The equation of the straight line passing through the points (0,3) and (-4,1) is  

⇒ 2(y - 1) = x + 4

⇒ 2y - 2 = x + 4

⇒ 2y = x + 6

⇒

Again, the equation of the line passing through the points (0,1) and (4,-1) is

⇒ - 2 ( y + 1) = x - 4

⇒ - 2y = x - 2

⇒

Therefore, the function is defined as

for x ≤ 0 ........... (1) and  

for x > 0 ............ (2)

Therefore, f(-2) = 2 from equation (1).

f(0) = 3 from equation (1)

And f (4) = -1 from equation (2). (Answer)

idk bring the function back   im not smart

step-by-step explanation:

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )