Based on outcomes since 1967, the probability a team from the national league wins the baseball world series in any given year is 0.44. based on outcomes since 1967, the probability a team from the national football conference wins the superbowl in any given year is 0.53. assume whether a team from the national league wins the world series in a year is independent of whether a team from the national football conference wins the superbowl in the same year. what is the probability a team from the national league wins the world series in a given year or a team from the national football conference wins the superbowl in the same year?

0.7368

Step-by-step explanation:

Let the occurrence that a team from the National League wins the Baseball World Series be termed EVENT A

and the occurrence that a team from the National Football Conference wins the Superbowl be termed EVENT B

We assumed that Event A and Event B are independent.

This means that the probability of Event A occurring is the same, whether or not Event B occurs, and vice versa.

P(Event A) = 0.44

P(Event B)= 0.53

P(Event A or Event B) = P(A) + P(B) - P(A and B)

The keywords here are "or" and "and".

To get P(A or B), let's find P(A and B)

P(A and B) = 0.44 × 0.53 = 0.2332

P(A or B) = 0.44 + 0.53 - 0.2332 = 0.97 - 0.2332 = 0.7368

the answer is 200

step-by-step explanation:

the way the question is worded, it seems to imply the $264 interest is simple interest, not compound interest.

the simple interest for 2 years is $264; the simple interest for 1 year is $132.

$132 interest on a $600 investment means an interest rate of (132/600)*100 = 22%.

the value of $200 at 22% interest compounded annually for three years is

200%281.22%29%5e3

the amount of interest is that value, minus the original $200.

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent