Which point is the solution to the following system of equations?
x² + y² = 13
2x- y=4
(-2, -3)
(-3, -2)
(2,3)
(3, 2)

The point (3, 2) is the solution to given system of equations

Solution:

Given that system of equations are:

   ------ eqn 1

   ------- eqn 2

From eqn 2,

y = 2x - 4

Substitute y = 2x - 4 in eqn 1

Let us solve the above equation by quadratic formula,

Using the Quadratic Formula for where  a = 5, b = -16, and c = 3

The discriminant so, there are two real roots.

Substitute for x = 0.2 and x = 3 in 2x - y = 4

when x = 3

2(3) - y = 4

6 - y = 4

y = 2

when x = 0.2

2(0.2) - y = 4

0.4 - y = 4

y = 0.4 - 4

y = -3.6

Thus Option D is correct The point is (3, 2)

no this is a nonlinear negative

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.