Find the equations of the two tangents to the curve y= 2x2 + 18 which pass through the origin.

The equations of the two tangents are and .

Step-by-step explanation:

The given curve is

          .... (1)

Let the point of tangency is at (a,b).

            .... (2)

Differentiate (1) with respect to x.

The slope of tangent is 4a.

It is given that tangent passes through the point (a,b) with slope 4a. So, equation of tangent is

where, m is slope.

        ... (3)

The line passes through the point (0,0).

            .... (4)

From (1) and (4) we get

Taking square root on both sides.

Substitute in equation (4).

The points of tangency are (3,36) and (-3,36).

Substitute the value of a and b in equation (3) to find the equations of tangents.

For (3,36),

For (-3,36),

Therefore, the equations of the two tangents are and .

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75

b.-4 units

all you   do is count how many times you move