Garage a charges $11 for the first 2 hours of parking there and then $3 per hour after the first 2 hours. garage b charges $4 per hours. after how many hours will the price be the same in both garages? (show work , it’s )

it would take 22 hours before you pay the same amount for both Garages.

Step-by-step explanation:

Let x represent the number of hours that you park at either Garage A or Garage B

Let y represent the total amount paid for x hours at Garage A

Let z represent the total amount paid for x hours at Garage B

Garage A charges $11 for the first 2 hours of parking there and then $3 per hour after the first 2 hours. This means that the total amount for x hours would be

y = 2 × 11 + 3x

y = 22 + 3x

Garage B charges $4 per hours. This means that the total amount for x hours would be

z = 4x

To determine the number of hours before the amount for both Garages becomes the same, we would equate y to z. It becomes

22 + 3x = 4x

4x - 3x = 22

x = 22

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.