What are the solutions of 3x2 + 14x + 16 = 0?

x = startfraction negative 8 over 3 endfraction, –2
x = –2, startfraction negative 3 over 8 endfraction
x = startfraction 3 over 8 endfraction, 2
x = startfraction 8 over 3 endfraction, 2

Good evening ,

x = StartFraction negative 8 Over 3 EndFraction, –2

Step-by-step explanation:

3x² + 14x + 16 = 0

3x² + 6x + 8x + 16 = 0

(3x² + 6x) + (8x + 16) = 0

3x(x+2) + 8(x+2) = 0

(x+2)(3x+8) = 0

x = -2  ,  x = -8/3.

:)

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

a reflection across the x axis and a 90 degree rotation left and right.