Solve for x in the equation x squared minus 8 x + 41 = 0.
x = - 4 ± √37 i
x = –4 ± 5i
x = 4± √37 i
x = 4 ± 5i

x = 4 ± 5i

Step-by-step explanation:

Just use the quadratic formula (ax²+bx+c=0) like you would for every other quadratic equation. Substitute i² for -1 when you get the square root of a negative number.

a = 1

b = -8

c = 41

Solution is x = (8 ± √(64-4·41)) / 2

x = 4 ± (√-100) / 2

x = 4 ± (√-25·4)/2

x = 4 ± √-25

x = 4 ± √(25i²)

x = 4 ± 5i

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

in english this is

ex.15 pag.85 create. write in ten lines the continuation of the ballad of the five motanasi, using verbs to the imperfect and to the perfect compound. five stars

hope i with whatever it is that you need! : )