For any two integers x + y, |x+y|=|x|+|y|

Sometimes true.

Step-by-step explanation:

The statement is sometimes true and sometimes false depending on the values of x and y.

Here's an example that shows it to be true.

|x+y|=|x|+|y|

Let x = 5 and y = 6.

|x+y|=5 + 6 = 11

|x|+|y| = |5| + +|6| = 5 + 6 = 11

In this case, both sides equal 11, and the expression is true.

Here's an example that shows it to be false.

|x+y|=|x|+|y|

Let x = -5 and y = 5.

|x+y|= |-5 + 5| = |0| = 0

|x|+|y| = |-5| + |5| = 5 + 5 = 10

The left side equals 0, and the right side equals 10. The sides are different, and the expression is false.

the line of

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!