The function f(t) = –16t2 + 250 represents the distance of a dropped object from the ground at any time, t. the equation g(t) = 15t represents the height of the object if it is tossed upward at a rate of 15 feet per second. the sum of the functions can be used to model the distance the dropped object is from the ground if it is tossed upward at a rate of 15 feet per second before it begins its descent.

which function models the sum?

h(t) = –16t2 + 265t
h(t) = –16t2 + 235t
h(t) = –16t2 – 15t + 250
h(t) = –16t2 + 15t + 250
.

the answer is 48m^2!

step-by-step explanation:

the answer is:

the correct option is the option b.

to calculate the surface area of the right cylinder, we need to use the following formula:

from the picture we know that:

so, substituting and calculting we have:

hence, we have that the correct option is the option b.

have a nice day!

ending amount = beginning amount / (2^n)

where "n" = number of half-lives (or elapsed time / half-life)

ending amount = 50 mg / (2 ^10 / 5.3)

ending amount = 50 mg / (2 ^ 1.8867924528)

ending amount = 50 m / 3.6981210597

ending amount = 13.5203794557 mg

or about 13.5 mg remain

source:  

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen