at a football game, a vender sold a combined total of 213 sodas and hot dogs. the number of sodas sold was two times the number of hot dogs sold. find the
number of sodas and the number of hot dogs sold.

142 sodas and 71 hot dogs are sold

Solution:

Let "a" be the number of sodas sold

Let "b" be the number of hot dogs sold

At a football game, a vender sold a combined total of 213 sodas and hot dogs

Therefore,

number of sodas sold + number of hot dogs sold = 213

a + b = 213 eqn 1

The number of sodas sold was two times the number of hot dogs sold

Number of sodas sold = two times the number of hot dogs sold

a = 2b eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 2 in eqn 1

2b + b = 213

3b = 213

b = 71

Substitute b = 71 in eqn 2

a = 2(71)

a = 142

Thus 142 sodas and 71 hot dogs are sold

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

no not all of them.

step-by-step explanation:

some of them have a square base.