Find the value of the sec 19° using your calculator. 0.946 1.011 0.989 1.058

Sec θ = 1/cosθ

sec 19° = 1/cos19°
   
             ≈   1/0.9455   ≈ 1.0576 ≈ 1.058

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

You need to include the original coordinates of the triangle to answer this. and how much does it translate (move left right up down)