A worm is at the bottom of a 10 foot hole he starts climbing out of the whole climbing 3 feet in one hour then he takes a break for one hour and slides backwards one foot but he repeats this pattern climbing at a constant rate of 3 ft./h and then sledding bag weighed to for one hour until he reaches the top if the wind begins growing at 7 AM what time will you be at the top of the hole

The worm  will be at the top of the hole at 4 PM

Step-by-step explanation:

The height of the hole  = 10 foot

Now at 8 AM, the the worm would have climbed 3 foot

At  9 AM the the worm would have slides 1 foot and will be at 2 foot

Now at 10 AM, the the worm would have climbed 3 foot and will be at 5 foot

At  11 AM the the worm would have slides 1 foot and will be at 4 foot

Now at 12 AM, the the worm would have climbed 3 foot and will be at 7 feet

At  1 PM the the worm would have slides 1 foot and will be at 6 foot

Now at 2 PM, the the worm would have climbed 3 foot and will be at 9 feet

At 3 PM the the worm would have slides 1 foot and will be at 8  foot

Now at 4 PM, the the worm would have climbed 11 foot

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

8

step-by-step explanation: