The activity completion time of each of the 5 critical activities of a project follows normal distribution. If the mean activity completion time of each activity is 2 weeks, and the standard deviation of the activity completion time of each of the critical activity is 10, then what is the probability that the project would take between 9 and 13 week?

P(x = 9) and P(x = 13) is:

0.6551965

Step-by-step explanation:

By Z score,

,

P(x = 9 ) =

P(x =13) =

And these give:

P(x = 9) ==>  P(Z = 0.7) = 0.7580363

P(x = 13) ==>  P(Z = 1.1) = 0.8643339

Therefore, the probability that the project would take between 9 and 13 week = P(x = 9) * P(x =13) =  0.6551965.

For replication, see the R codes below:

Z1 = (9 - 2)/(10/sqrt(length(5)))

a = pnorm(Z1)

Z2 = (13 - 2)/(10/sqrt(length(5)))

b = pnorm(Z2)

a*b

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

read more on -

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of