It was recently estimated that homes without children outnumber homes with children by about seven to five. If there are 2556 homes in a county, how many of them are homes without children?

929  

Step-by-step explanation:

For every 11 children, 7 will have homes and 4 will not.

The fraction of children without homes is 4/11.

The number of children without homes is

4/11 × 2556 = 929

Check:

The number of children with homes is 2556 - 929 = 1627

With/Without = 1627/929 = 7.005/4 ≈ 7/4

OK.

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )