Solve this problem.
The length of the smaller rectangle at the right is 1 inch less than
twice its width. Both the dimensions of the larger rectangle are 2
inches longer than the smaller rectangle. The area of the shaded
region is 86 square inches. What is the area of the larger
rectangle?

Let x = the width of the smaller rectangle.

The length of the smaller rectangle is 2x - 1.

Area is A = lw

So the area of the smaller rectangle is A = (x)(2x - 1) = 2x^2 - x

Step-by-step explanation:

hope it helped

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

d. you cannot tell because there are no values shown.