You own a small storefront retail business and are interested in determining the average amount of money a typical customer spends per visit to your store. You take a random sample over the course of a month for 26 customers and find that the average dollar amount spent per transaction per customer is $77.506 with a standard deviation of $11.0714. When creating a 99% confidence interval for the true average dollar amount spend per customer, what is the margin of error

Step-by-step explanation:

Hello!

The Confidence intervals for the population mean to follow the structure "point estimation"±" margin of error"

You as the store owner took a sample to determine the average amount of money a typical customer spends on your shop.

n= 26 customers.

X[bar]= $77.506

S= $11.0714

Assuming the variable X: the amount of money spent by a typical customer has a normal distribution and that there is no information about the population standard deviation, the best statistic to use for this estimation is a Students-t:

[X[bar] ± * ]

The margin of error of the interval is:

d= *

d= 6.051

I hope it helps!

answer: there are x+184 pages in olivia's book.

step-by-step explanation:

let the total number of pages in the book which olive has already read be x.

then if olive has 184 pages left to read, then the total number of pages are in olive's book= pages she has read+pages she has left to read

therefore, the total number of pages in olivia's book=

hence, there are x+184 pages in olivia's book.

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared