Plz me fast! given that ∠mql = 180° and ∠xqr = 180°, which equation could be used to solve problems involving the relationships between ∠mqr and ∠xql?
a) (−5b + 115) = (125 − 10b)
b) (−5b + 115) + (125 − 10b) = 180
c) (−5b + 115) − (125 − 10b) = 180
d) (−5b + 115) − 180 = (125 − 10b)

Given

∠MQL=180°

∠XQR=180°

Hence ∠MQL=∠XQR

(We know that ∠MQL is the sum of ∠MQR and ∠RQL

and ∠XQR is the sum of ∠XQM and ∠MQR)

lets plug in these in our equation

∠MQL=∠XQR

∠MQR + ∠RQL = ∠XQM + ∠MQR

We can cancel out ∠MQR

hence ∠RQL = ∠XQM

hence we can infer that the opposite angles of intersecting lines are equal

similarly

∠MQR = ∠XQL

which is

125-10b = -5b+115

Hence the right option is A)

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2