Can someone help me out please?

h = √(44) ft

Step-by-step explanation:

Just looked back and A is actually the area because the unit was ft².

Area of a right isosceles triangle is half the area of a square.

A = ½S²

in this case your side is h.

A = ½h²

2A = h²

√(2A) = h

√(2(22)) = h

√(44) = h

plug that in your calculator for the answer.

≅ 6.63

Step-by-step explanation:

Area of the triangle=

The Base and height of the triangle is given i.e 'h'.

Area of the triangle=

The value of 'h' is

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.