In the picture below, D is the midpoint of AB, CE/DE = 5/3, BF/EF = 1/3. If the ABC triangle's area is 192u², what's the BDF triangle area?
Obs : I'm literally 4 hours trying to solve this problem. I've been trying to answer other similar questions that took hours to solve, and, when i ask here at everyone solves the problem in less than 10 minutes, that makes me think i'm intelligent as potato(which isn't a lie), the only thing i'm asking for after the problem's answer is some motivational stuff 'cause i'm almost giving up.

With these 5 geometry questions! pls 1.)quadrilateral abcd is inscribed in this circle.what is the measure of ∠a ? enter your answer in the box.°2.)quadrilateral abcd is inscribed in a circle.what is the measure of angle a? enter your answer in the box.m∠a= 3.)quadrilateral abcd is inscribed in this circle.what is the measure of angle b? enter your answer in the box.m∠b= °4.)quadrilateral abcd is inscribed in this circle.what is the measure of angle a? enter your answer in the box.°5.) quadrilateral abcd is inscribed in this circle.what is the measure of angle c? enter your answer in the box.°

What unit of been sure would be appropriate for the volume of a sphere with a radius of 2 meters

Given: ae ≅ ce ; de ≅ be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that △aeb ≅ △ced, we can show that △ ≅ △ceb by. so, ∠cad ≅ ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.