Let L be the line with parametric equations x = 7 − t y = −3t z = −2 find the vector equation for a line that passes through the point P(8, −10, −1) and intersects L at a point that is distance 4 from the point Q = (7, 0, −2). Note that there are two possible correct answers.

Look, when you want to do something like put it like x^2. x2 could mean x² or x₂. so to clear confusion, know the notation. to find the product multiply the x's and you get -8x and the y's and you get 6y. since it's all being multiplied it is just -8x6y, or answer a. although the better answer is -48xy(combining -8 and 6) because you should multiply constants whenever you can.

The answer is b.$19.99  hope this : )