If you are given the graph of h(x) = log6X, how could you graph m(x) =log6(X+3)?
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Translate each point of the graph of h(x) 3 units up.
Translate each point of the graph of h(x) 3 units down.
Translate each point of the graph of h(x) 3 units right.
Translate each point of the graph of h(x) 3 units left.

Translate each point of the graph of h(x) 3 units left ⇒ 4th answer

Step-by-step explanation:

Let us revise the translation of a graph

∵

∵  

∵ x in h(x) is changed to (x + 3) in m(x)

- From the 2nd rule above, that means the graph of h(x)

   is translated 3 units to the left

∴ The graph of h(x) is translated 3 units to the left

∴ Each point on the graph of h(x) is translated 3 units to the left

∴ Translate each point of the graph of h(x) 3 units left

Look to the attached figure to more understand

The red line represents h(x)

The blue line represents m(x)

thats not a system of equations, that is a solution

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)